4x^2+45x+50=0

Solution for 4x^2+45x+50=0 equation:

4x^2+45x+50=0

a = 4; b = 45; c = +50;
Δ = b2-4ac
Δ = 452-4·4·50
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-35}{2*4}=\frac{-80}{8}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+35}{2*4}=\frac{-10}{8}
=-1+1/4
$